4x^2+3y^2=16

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Solution for 4x^2+3y^2=16 equation:


Simplifying
4x2 + 3y2 = 16

Solving
4x2 + 3y2 = 16

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3y2' to each side of the equation.
4x2 + 3y2 + -3y2 = 16 + -3y2

Combine like terms: 3y2 + -3y2 = 0
4x2 + 0 = 16 + -3y2
4x2 = 16 + -3y2

Divide each side by '4'.
x2 = 4 + -0.75y2

Simplifying
x2 = 4 + -0.75y2

Reorder the terms:
-4 + x2 + 0.75y2 = 4 + -0.75y2 + -4 + 0.75y2

Reorder the terms:
-4 + x2 + 0.75y2 = 4 + -4 + -0.75y2 + 0.75y2

Combine like terms: 4 + -4 = 0
-4 + x2 + 0.75y2 = 0 + -0.75y2 + 0.75y2
-4 + x2 + 0.75y2 = -0.75y2 + 0.75y2

Combine like terms: -0.75y2 + 0.75y2 = 0.00
-4 + x2 + 0.75y2 = 0.00

The solution to this equation could not be determined.

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